# UART Support for Pmod IOPs?

**URL:** https://discuss.pynq.io/t/uart-support-for-pmod-iops/1961
**Category:** Support
**Created:** [October 29, 2020, 9:09pm UTC](https://discuss.pynq.io/t/uart-support-for-pmod-iops/1961 "2020-10-29T21:09:50Z")
**Posts on this page:** 3
**Page:** 1

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### Author: ![VicerExciser](https://sea1.discourse-cdn.com/flex019/user_avatar/discuss.pynq.io/vicerexciser/32/1643_2.png) [@VicerExciser](https://discuss.pynq.io/u/VicerExciser)
#### Post date: [October 29, 2020, 9:09pm UTC](https://discuss.pynq.io/t/uart-support-for-pmod-iops/1961/1 "2020-10-29T21:09:50Z")

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I’ve noticed that the [block diagram for the Pmod IOPs](https://pynq.readthedocs.io/en/v2.6.1/pynq_libraries/pmod.html#block-diagram) indicates that the Pmod interfaces do not support the UART API (‘uart.h’).

Is this true? Or are the Pmod pins capable of UART?

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### Author: ![cathalmccabe](https://sea1.discourse-cdn.com/flex019/user_avatar/discuss.pynq.io/cathalmccabe/32/3348_2.png) [@cathalmccabe](https://discuss.pynq.io/u/cathalmccabe)
#### Post date: [November 4, 2020, 8:20am UTC](https://discuss.pynq.io/t/uart-support-for-pmod-iops/1961/2 "2020-11-04T08:20:46Z")

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Yes, this is correct.  
The Pmod pins are just “pins” so yes, they are capable of supporting UART.

Cathal

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### Author: ![AllenChenChao](https://avatars.discourse-cdn.com/v4/letter/a/7bcc69/32.png) [@AllenChenChao](https://discuss.pynq.io/u/AllenChenChao)
#### Post date: [November 19, 2020, 3:10am UTC](https://discuss.pynq.io/t/uart-support-for-pmod-iops/1961/3 "2020-11-19T03:10:29Z")

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> [@VicerExciser](#):
>
> that the [block diagram for the Pmod IOPs](https://pynq.readthedocs.io/en/v2.6.1/pynq_libraries/pmod.html#block-diagram) indicates that the Pmod interfaces do not support the UART API (‘uart.h’).
> 
> Is this true? Or are the Pmod pins capable of UART?
> 
> > [@](#):
> >
> > Yes, this is correct. The Pmod pins are just “pins” so yes, they are capable of supporting UART. Cathal

Hi, Is PMOD uart support by base.bit? It means a software engineer could obtain the usege of it.  
Thank you, I remember that you have already answer a lot of question well. Thank you very much.
